Question 71
Let $ABC$ be a triangle, and let $M$ and $N$ be the respective midpoints of $AB$ and $AC$. Suppose that
$$
\frac{CM}{AC} = \frac{\sqrt{3}}{2}
$$
Prove that
$$
\frac{BN}{AB} = \frac{\sqrt{3}}{2}
$$
$$
\frac{CM}{AC} = \frac{\sqrt{3}}{2}
$$
Prove that
$$
\frac{BN}{AB} = \frac{\sqrt{3}}{2}
$$