Question 38
**Can real numbers $x$, $y$, $z$ satisfy**
$$
\frac{1}{(x-y)(x+y)} + \frac{1}{(y-z)(y+z)} + \frac{1}{(z-x)(z+x)} = 0?
$$
$$
\frac{1}{(x-y)(x+y)} + \frac{1}{(y-z)(y+z)} + \frac{1}{(z-x)(z+x)} = 0?
$$
MathNet 2026 — Part 08 Question 38
Math Olympiad Vault · MathNet 2026 — Part 08