Question 167
Point $P$ on side $BC$ of triangle $ABC$ satisfies
$$
|BP| : |PC| = 2 : 1
$$
Prove that the line $AP$ bisects the median of triangle $ABC$ drawn from vertex $C$.
$$
|BP| : |PC| = 2 : 1
$$
Prove that the line $AP$ bisects the median of triangle $ABC$ drawn from vertex $C$.