Question 102
Solve for $c$ in the following system of equations:
$$
\begin{aligned}
& 16^{a+b} = \frac{\sqrt{2}}{2} \\
& 16^{b+c} = 4 \\
& 16^{a+c} = 2 \sqrt{2}
\end{aligned}
$$
(a) 0
(b) $\frac{3}{8}$
(c) $\frac{5}{8}$
(d) $\frac{1}{2}$
$$
\begin{aligned}
& 16^{a+b} = \frac{\sqrt{2}}{2} \\
& 16^{b+c} = 4 \\
& 16^{a+c} = 2 \sqrt{2}
\end{aligned}
$$
(a) 0
(b) $\frac{3}{8}$
(c) $\frac{5}{8}$
(d) $\frac{1}{2}$