Question 111
Let $ABCD$ be a square and let $\Gamma$ denote the circle with diameter $CD$. A tangent line is drawn to the circle $\Gamma$ from $B$, meeting the circle $\Gamma$ at $E$ and intersecting the segment $AD$ at $K$.
Prove that $|AD| = 4|KD|$.
Prove that $|AD| = 4|KD|$.