Question 181
Let
$$ f(n) = 4n^4 + 7n^2 + 3n + 6. $$
Prove that if $n$ is an integer, then $f(n)$ is not the cube of an integer.
$$ f(n) = 4n^4 + 7n^2 + 3n + 6. $$
Prove that if $n$ is an integer, then $f(n)$ is not the cube of an integer.
MathNet 2026 — Part 05 Question 181
Math Olympiad Vault · MathNet 2026 — Part 05