Question 133
Find all solutions in positive integers of the equation
$$
x^{4} + y^{4} + z^{4} + 1008 = 2x^{2}y^{2} + 2y^{2}z^{2} + 2z^{2}x^{2}.
$$
$$
x^{4} + y^{4} + z^{4} + 1008 = 2x^{2}y^{2} + 2y^{2}z^{2} + 2z^{2}x^{2}.
$$
MathNet 2026 — Part 05 Question 133
Math Olympiad Vault · MathNet 2026 — Part 05