Question 89
Determine the real solutions of the equation
$$
\sqrt{2x^2 + 2x + 3} + \sqrt{2x^2 + 2} = \sqrt{3x^2 + 2x - 1} + \sqrt{x^2 + 6}.
$$
$$
\sqrt{2x^2 + 2x + 3} + \sqrt{2x^2 + 2} = \sqrt{3x^2 + 2x - 1} + \sqrt{x^2 + 6}.
$$
MathNet 2026 — Part 05 Question 89
Math Olympiad Vault · MathNet 2026 — Part 05