Question 141
be $\omega_{1}$ and $\omega_{2}$ two disjointed circles. a common tangent external to these two circles cuts $\omega_{1}$ in $A$ and $\omega_{2}$ in $B$. the second common tangent external to these two circles cuts $\omega_{1}$ in $D$ and $\omega_{2}$ in $C$. The right $(BD)$ cut $\omega_{1}$ at the point $P$ other than $D$ and $\omega_{2}$ at the point $Q$ other than $B$. To show that $BQ = DP$.