Question 165
Solve the following system of equations:
$$
\begin{cases} x^4 - y^4 = 240 \\ x^3 - 2y^3 = 3(x^2 - 4y^2) - 4(x - 8y). \end{cases}
$$
$$
\begin{cases} x^4 - y^4 = 240 \\ x^3 - 2y^3 = 3(x^2 - 4y^2) - 4(x - 8y). \end{cases}
$$
MathNet 2010 — Part 07 Question 165
Math Olympiad Vault · MathNet 2010 — Part 07