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MathNet 2010 — Part 06 Question 81

Math Olympiad Vault · MathNet 2010 — Part 06

Question 81

For a real number $t$ and positive real numbers $a$ and $b$ we have
$$
2a^2 - 3abt + b^2 = 2a^2 + abt - b^2 = 0.
$$
Find $t$.