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MathNet 2010 — Part 06 Question 50

Math Olympiad Vault · MathNet 2010 — Part 06

Question 50

They dug a pit in the shape of a cube. Its depth is 12 times greater than its length. The length of the cave is $\frac{3}{2}$ its width. The sum of the measurement number of the volume of the cave and the area of its bottom is $\frac{7}{6}$. Calculate the depth of the pit.