Question 94
Two Distinct Real Numbers $a$ and $b$ Are Chosen in such a way that the equation
$$
(x^2 + 20a x + 10b)(x^2 + 20b x + 10a) = 0
$$
has no real roots. Prove that the number $20(b-a)$ is not an integer. different real numbers $a$ and $b$ such that the equation
$$
(x^2 + 20a x + 10b)(x^2 + 20b x + 10a) = 0
$$
has no roots. Prove that the number $20(b - a)$ is not whole.
$$
(x^2 + 20a x + 10b)(x^2 + 20b x + 10a) = 0
$$
has no real roots. Prove that the number $20(b-a)$ is not an integer. different real numbers $a$ and $b$ such that the equation
$$
(x^2 + 20a x + 10b)(x^2 + 20b x + 10a) = 0
$$
has no roots. Prove that the number $20(b - a)$ is not whole.