Question 131
Given is a square $ABCD$ with circumscribed circle $\Gamma_{1}$. They are $P$ a point on arch $AC$ which also contains $B$. A circle $\Gamma_{2}$ touches $\Gamma_{1}$ internally in $P$ and also touches diagonally $AC$ in $Q$. They $R$ a point on $\Gamma_{2}$ so that the line $DR$ touches $\Gamma_{2}$. Prove that $|DR| = |DA|$.