Question 160
A point $P$ is located in the interior of a triangle $ABC$. If
$$
AP = \sqrt{3},\ BP = 5,\ CP = 2,\ AB : AC = 2 : 1,\ \angle BAC = 60^\circ,
$$
what is the value of the area of the triangle $ABC$?
Here by $XY$ we represent the length of the line segment $XY$.
$$
AP = \sqrt{3},\ BP = 5,\ CP = 2,\ AB : AC = 2 : 1,\ \angle BAC = 60^\circ,
$$
what is the value of the area of the triangle $ABC$?
Here by $XY$ we represent the length of the line segment $XY$.