Question 127
A base $ABC$ isosceles triangle $AC$ is given. Within this triangle are given a point $M$, on the part of $C$ with respect to the axis of $AC$ and such that $C\widehat{M}A = 2C\widehat{B}A$, and a point $N$ within the $AM$ segment such that $B\widehat{N}M = C\widehat{B}A$. - Prove that $C\widehat{B}N = B\widehat{A}M$. - Prove that $CM + MN = BN$.