Question 80
Prove that
$$
\frac{a^2}{a+b} + \frac{b^2}{b+c} \ge \frac{3a+2b-c}{4}
$$
for all positive real $a, b, c$.
(D. Pirshtuk)
$$
\frac{a^2}{a+b} + \frac{b^2}{b+c} \ge \frac{3a+2b-c}{4}
$$
for all positive real $a, b, c$.
(D. Pirshtuk)
MathNet 2010 — Part 01 Question 80
Math Olympiad Vault · MathNet 2010 — Part 01