Question 2
Show that there are only finitely many solutions to
$$
\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{1}{1983}
$$
in positive integers.
$$
\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{1}{1983}
$$
in positive integers.
MathNet 1983 — Part 01 Question 2
Math Olympiad Vault · MathNet 1983 — Part 01