Question 72
It is given that $f(x)$ is a function defined on $\mathbb{R}$, satisfying $f(1) = 1$, and for any $x \in \mathbb{R}$,
$$
f(x+5) \ge f(x)+5,
$$
and $f(x+1) \le f(x)+1$.
If $g(x) = f(x)+1-x$, then $g(2002) = \underline{\hspace{2cm}}$.
$$
f(x+5) \ge f(x)+5,
$$
and $f(x+1) \le f(x)+1$.
If $g(x) = f(x)+1-x$, then $g(2002) = \underline{\hspace{2cm}}$.