Question 6
How many real numbers $x$ are solutions to the following equation?
$$
2003^{x} + 2004^{x} = 2005^{x}
$$
$$
2003^{x} + 2004^{x} = 2005^{x}
$$
MathNet 2005 — Part 01 Question 6
Math Olympiad Vault · MathNet 2005 — Part 01
Math Olympiad Vault · MathNet 2005 — Part 01