Question 180
Solve the equation system
$$
\begin{cases} 1 - \dfrac{12}{y+3x} = \dfrac{2}{\sqrt{x}} \\[2mm] 1 + \dfrac{12}{y+3x} = \dfrac{6}{\sqrt{y}} \end{cases}
$$
$$
\begin{cases} 1 - \dfrac{12}{y+3x} = \dfrac{2}{\sqrt{x}} \\[2mm] 1 + \dfrac{12}{y+3x} = \dfrac{6}{\sqrt{y}} \end{cases}
$$