Question 25A semicircle is inscribed in an isosceles triangle with base $16$ and height $15$ so that the diameter of the semicircle is contained in the base of the triangle as shown. What is the radius of the semicircle? $ 4 \sqrt{3} $$ \dfrac{120}{17} $$ 10 $$ \dfrac{17\sqrt{2}}{2} $$ \dfrac{17\sqrt{3}}{2} $
