Question 15
In base ten, $923=9\cdot10^2+2\cdot10+3$. In base five the digits are $\{0,1,2,3,4\}$, so $321_5=3\cdot5^2+2\cdot5+1$. What is the base-five representation of the decimal number 237? Source note: the original list of decimal digits accidentally omits 6; the full list is $\{0,1,2,3,4,5,6,7,8,9\}$.
