Question 20
The 2022nd term of the sequence below is $m/n$ in lowest terms, with $\operatorname{HCF}(m,n)=1$. Find $n-m$. $$\frac12,\frac13,\frac14,\frac24,\frac15,\frac25,\frac16,\frac26,\frac36,\frac17,\frac27,\frac37,\ldots$$
Interpretation: Continue by increasing denominator d = 2, 3, 4, …; for each d list numerators 1 through floor(d/2) in order. Repeated equal fractions remain separate terms, and term 1 is 1/2.
Answer format: an integer without units. Leading zeros are optional; the source uses four digit boxes.
Interpretation: Continue by increasing denominator d = 2, 3, 4, …; for each d list numerators 1 through floor(d/2) in order. Repeated equal fractions remain separate terms, and term 1 is 1/2.
Answer format: an integer without units. Leading zeros are optional; the source uses four digit boxes.