Question 10A triangle has area $30,$ one side of length $10,$ and the median to that side of length $9.$ Let $\theta$ be the acute angle formed by that side and the median. What is $\sin\theta?$$\dfrac{3}{10}$$\dfrac{1}{3}$$\dfrac{9}{20}$$\dfrac{2}{3}$$\dfrac{9}{10}$