Question 11A square and an equilateral triangle have the same perimeter. Let $A$ be the area of the circle circumscribed about the square and $B$ be the area of the circle circumscribed about the triangle. Find $\frac{A}{B}.$$\dfrac{9}{16}$$\dfrac{3}{4}$$\dfrac{27}{32}$$\dfrac{3\sqrt{6}}{8}$$1$