Question 3
According to the standard convention for exponentiation, $$
2^{2^{2^2}} = 2^{\left(2^{\left(2^2\right)}\right)} = 2^{16} = 65{,}536.
$$ If the order in which the exponentiations are performed is changed, how many other values are possible?
2^{2^{2^2}} = 2^{\left(2^{\left(2^2\right)}\right)} = 2^{16} = 65{,}536.
$$ If the order in which the exponentiations are performed is changed, how many other values are possible?