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2001 AMC 12 Question 24

AMC12 · 2001 AMC 12

Question 24

In triangle $ABC,$ $\angle ABC = 45^\circ.$ Point $D$ is on $\overline{BC}$ so that $2 \cdot BD = CD$ and $\angle DAB = 15^\circ.$ Find $\angle ACB.$

Question illustration
  1. $54^\circ$
  2. $60^\circ$
  3. $72^\circ$
  4. $75^\circ$
  5. $90^\circ$