Skip to content / Đến nội dung
ThichHocToan.com

1996 AMC 12 Question 17

AMC12 · 1996 AMC 12

Question 17

In rectangle $ABCD,$ angle $C$ is trisected by $\overline{CF}$ and $\overline{CE},$ where $E$ is on $\overline{AB},$ $F$ is on $\overline{AD},$ $BE=6,$ and $AF=2.$ Which of the following is closest to the area of the rectangle $ABCD?$

Question illustration
  1. $110$
  2. $120$
  3. $130$
  4. $140$
  5. $150$