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1985 AMC 12 Question 30

AMC12 · 1985 AMC 12

Question 30

Let $\lfloor x\rfloor$ be the greatest integer less than or equal to $x.$ Then the number of real solutions to $4x^2-40\lfloor x\rfloor+51=0$ is
  1. $0$
  2. $1$
  3. $2$
  4. $3$
  5. $4$