Question 8Let $a,$ $a',$ $b,$ $b'$ be real numbers with $a$ and $a'$ nonzero. The solution to $ax+b=0$ is less than the solution to $a'x+b'=0$ if and only if$a'b\lt ab'$$ab'\lt a'b$$ab\lt a'b'$$\frac ba\lt\frac{b'}{a'}$$\frac{b'}{a'}\lt\frac ba$