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1978 AMC 12 Question 4

AMC12 · 1978 AMC 12

Question 4

If $a=1,$ $b=10,$ $c=100$ and $d=1000,$ then $$
\begin{aligned} &(a+b+c-d)+(a+b-c+d)\\ &\quad+(a-b+c+d)\\ &\quad+(-a+b+c+d) \end{aligned}
$$ is equal to
  1. $1111$
  2. $2222$
  3. $3333$
  4. $1212$
  5. $4242$