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IKMC 2011 - Grades 11-12 - Paper 02 - Self-study Question 8

IKMC · IKMC 2011 - Grades 11-12 - Paper 02 - Self-study

Question 8

Quadrilateral PQRS satisfies PS=SR, angles PSR=PQR=90°, ST perpendicular to PQ, and ST=5. Find its area.

Editorial note: the source prints an infinity-like symbol between ST and PQ. The right-angle mark in the figure establishes ST perpendicular to PQ; that is the condition used here.

Question illustration
  1. 20
  2. 22.5
  3. 25
  4. 27.5
  5. 30