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ITMC 2018 Grade 11 National Preliminary set01 Question 10

ITMC · ITMC 2018 Grade 11 National Preliminary set01

Question 10

Given $37^x=\sqrt[3]{20}+\sqrt[3]{17}$ and $37^y=\sqrt[3]{400}-\sqrt[3]{340}+\sqrt[3]{289}$, which relation is correct?
  1. $y=-x+1$
  2. $y=-x+\log37$
  3. $y=1/x$
  4. $y=(\log37)/x$
  5. None of these