Question 11The limit of the sum of an infinite number of terms in a geometric progression is $\dfrac{a}{1-r},$ where $a$ denotes the first term and $-1\lt r\lt1$ denotes the common ratio. The limit of the sum of their squares is:$\dfrac{a^2}{(1-r)^2}$$\dfrac{a^2}{1+r^2}$$\dfrac{a^2}{1-r^2}$$\dfrac{4a^2}{1+r^2}$None of these