Question 29
Positive integers $m,n$ satisfy
$$\frac mn=\frac1{10\cdot12}+\frac1{12\cdot14}+\frac1{14\cdot16}+\cdots+\frac1{2012\cdot2014}.$$
Find the smallest possible $m+n$.
$$\frac mn=\frac1{10\cdot12}+\frac1{12\cdot14}+\frac1{14\cdot16}+\cdots+\frac1{2012\cdot2014}.$$
Find the smallest possible $m+n$.