Question 13
In parallelogram $ABCD$, $E$ is the midpoint of $AD$, $H$ is the midpoint of $AB$. $G$, $F$ and $K$ are points on $BC$, $CD$ and $CA$ respectively such that $BG=2GC$, $DF=3FC$ and $2CK=3KA$. The area of parallelogram $ABCD$ is $240$ $\mathrm{cm}^2$. What is the difference between the areas, in $\mathrm{cm}^2$, of triangles $EFK$ and $HKG$?
