Question 14
In square $ABCD$, $\angle PCB=\angle QDC=\angle RAD=\angle SBA$, as shown. If $[ABCD]=2[PQRS]$, find $\angle PCB$ in degrees.
IMC 2013 — Keystage 3 (IWYMIC) — individual Question 14
xIMC · IMC 2013 — Keystage 3 (IWYMIC) — individual
xIMC · IMC 2013 — Keystage 3 (IWYMIC) — individual