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1991 AMC 8 Question 4

AMC8 · 1991 AMC 8

Question 4

If $991 + 993 + 995$ $+ 997 + 999$ $= 5000 - N,$ then $N = $
  1. $5$
  2. $10$
  3. $15$
  4. $20$
  5. $25$