Question 2In the diagram below, $ABCD$ is a rectangle, where $AB=8$ cm and $BC=4$ cm. Let the angle bisector from $D$ intersect $AB$ at $E$. Find the distance, in cm, from $E$ to $AC$. $\frac{3\sqrt2}{2}$$\frac{4\sqrt2}{5}$$\frac{4\sqrt5}{5}$$\frac{2\sqrt5}{5}$$\frac{4\sqrt2}{5}$