Question 10
As shown, $ABCDE$ is a convex pentagon with $AB=BC$, $\angle EAB=110^\circ$, $\angle CDE=80^\circ$ and $\angle DEA=100^\circ$. The bisectors of $\angle EAB$ and $\angle BCD$ meet at $F$. Find $\angle ABF$ in degrees.


IMAS · IMAS 2025–2026 Upper Primary — Round 2
