Question 68
(a) SE $r=\sqrt{2}+\sqrt{3}$, show that $\sqrt{6}=\frac{r^{2}-5}{2}$.
(b) SE $s=\sqrt{215}+\sqrt{300}$, show that $s^{2}\gt 1015$.
(b) SE $s=\sqrt{215}+\sqrt{300}$, show that $s^{2}\gt 1015$.
MathNet 2026 — Part 01 Question 68
Math Olympiad Vault · MathNet 2026 — Part 01