Question 5
In the diagram below, $ABC$ is a triangle, where $E$ is a point on $AC$ and $F$ is a point on $AB$. The lines $BE$ and $CF$ intersect at $D$. If the ratio of the areas of the triangles $BDF$ and $CDE$ is $5:16$, the ratio of the areas of the triangles $AFD$ and $AED$ is $5:8$ and the area of the triangle $BCD$ is $18\text{ cm}^2$, what is the area, in $\text{cm}^2$, of the triangle $ABC$?
